7=x*23,35^2*2,3

Solution for 7=x*23,35^2*2,3 equation:

7=x*23.35^2*2.3

We move all terms to the left:

7-(x*23.35^2*2.3)=0

We get rid of parentheses

-x*23.35^2*2.3+7=0

Wy multiply elements

-52.9x^2+7=0

a = -52.9; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·(-52.9)·7
Δ = 1481.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1481.2}}{2*-52.9}=\frac{0-\sqrt{1481.2}}{-105.8}
=-\frac{\sqrt{}}{-105.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1481.2}}{2*-52.9}=\frac{0+\sqrt{1481.2}}{-105.8}
=\frac{\sqrt{}}{-105.8}
$